oracle 函数判断字符串是否包含图片格式的实例代码
首先是写一个分割字符串的函数，返回table类型CREATE OR REPLACE FUNCTION fn_split (p_str IN VARCHAR2, p_delimiter IN VARCHAR2)
RETURN ty_str_split
IS
j INT := 0;
i INT := 1;
len INT := 0;
len1 INT := 0;
str VARCHAR2 (4000);
str_split ty_str_split := ty_str_split ();
BEGIN
len := LENGTH (p_str);
len1 := LENGTH (p_delimiter);
WHILE j < len
LOOP
j := INSTR (p_str, p_delimiter, i);
IF j = 0
THEN
j := len;
str := SUBSTR (p_str, i);
str_split.EXTEND;
str_split (str_split.COUNT) := str;
IF i >= len
THEN
EXIT;
END IF;
ELSE
str := SUBSTR (p_str, i, j - i);
i := j + len1;
str_split.EXTEND;
str_split (str_split.COUNT) := str;
END IF;
END LOOP;
RETURN str_split;
END fn_split;上面这个函数可以将字符串分割返回table
create or replace function fn_ispng(
strpngin varchar2
) return number is
v_numnumber;
begin
WITH t1 AS
(select * from table (fn_split(strpng,'.'))
)
select count(1) into v_num from t1 where t1.column_value in ('png', 'jpg','jpeg','gif','bmp','eps');
return v_num;
end fn_ispng;上面这个是判断是否是图片格式，的图片格式返回1
select fn_ispng('dfdfd.png') from dual;以上所述是小编给大家介绍的oracle 函数判断字符串是否包含图片格式，希望对大家有所帮助，如果大家有任何疑问请给我留言，小编会及时回复大家的。在此也非常感谢大家对CodeAE代码之家网站的支持！
https://www.uoften.com/dbs/oracle/20180415/73930.html
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