Linux系统中获取路径的文件名的方法
这篇文章主要介绍了Linux系统中获取路径的文件名的方法,文中总结出了两条,需要的朋友可以参考下代码如下:
#basename /root/aaa/bbb/dabu.txt
显示：
dabu.txt #获取路径的文件名
shell脚本中如何获得脚本文件所在路径？
方法一：
#DIR=$(cd "$(dirname "$0")"; pwd)</p> <p>#echo $DIR但是像这种dirname "$0"这种写法，在遇到source命令时会得到错误的结果。
方法二：
#echo "$( cd "$( dirname "${BASH_SOURCE}" )" && pwd )"上面一行命令可以获得脚本的绝对轮径，无论你在何处调用这个脚本。
但是如果含有软链接，就无法使用了。所以，我们为了能正确解析指向脚本的软链接，可以使用下面的多行命令：
SOURCE="${BASH_SOURCE}"
while [ -h "$SOURCE" ]; do # resolve $SOURCE until the file is no longer a symlink
DIR="$( cd -P "$( dirname "$SOURCE" )" && pwd )"
SOURCE="$(readlink "$SOURCE")"
[[ $SOURCE != /* ]] && SOURCE="$DIR/$SOURCE" # if $SOURCE was a relative symlink, we need to resolve it relative to the path where the symlink file was located
done
DIR="$( cd -P "$( dirname "$SOURCE" )" && pwd )"也可与source,bash -c命令使用
但是，如果你在脚本中使用先cd切换到其他目录，在运行时上面的命令片段时，则上面的命令不能等到正确的结果。可以参考关于$CDPATH 陷阱的文章。想理解它如何其作用的，可以运行下面的代码：
#!/bin/bash</p> <p> SOURCE="${BASH_SOURCE}"
while [ -h "$SOURCE" ]; do # resolve $SOURCE until the file is no longer a symlink
TARGET="$(readlink "$SOURCE")"
if [[ $SOURCE == /* ]]; then
echo "SOURCE '$SOURCE' is an absolute symlink to '$TARGET'"
SOURCE="$TARGET"
else
DIR="$( dirname "$SOURCE" )"
echo "SOURCE '$SOURCE' is a relative symlink to '$TARGET' (relative to '$DIR')"
SOURCE="$DIR/$TARGET" # if $SOURCE was a relative symlink, we need to resolve it relative to the path where the symlink file was located
fi
done
echo "SOURCE is '$SOURCE'"
RDIR="$( dirname "$SOURCE" )"
DIR="$( cd -P "$( dirname "$SOURCE" )" && pwd )"
if [ "$DIR" != "$RDIR" ]; then
echo "DIR '$RDIR' resolves to '$DIR'"
fi
echo "DIR is '$DIR'"
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