有没有 更简便的根据最大值和最小值的差值 等距分组的方法
分组的小技巧，不知道有没现成的函数可以计算出来各自对应的分组select policy_id
,reserve_amount_first
,min_coins_indemnity_fee
,max_coins_indemnity_fee
,round((reserve_amount_first-min_coins_indemnity_fee + line_space/10)/(line_space ) ,0) as level as level # 分组从1开始
from (select *,'1' as key from dat_month a where pt='20181130000000'
and reserve_amount_first is not null ) a join (
select
'1' as key
,min(reserve_amount_first ) min_coins_indemnity_fee
,max(reserve_amount_first ) max_coins_indemnity_fee
,(max(reserve_amount_first ) -min(reserve_amount_first ) ) /10 as line_space
from dat_month where pt='20181130000000' and reserve_amount_first is not null
) b on a.key=b.key
limit 100;
https://blog.51cto.com/u_8649447/4868469
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