oracle RETURNING 子句使用方法
RETURNING 自己通常结合DML 语句使用。(INSERT UPDATE DELETE)使用方法:
UPDATE table_name SET expr1
RETURNING column_name
INTO xxxINSERT: 返回的是添加后的值
UPDATE:返回时更新后的值
DELETE:返回删除前的值
RETURNING 可以再sqlplus 和plsql中使用
如果是plsql就如上面的代码,xxx为声明的变量名
如果是sqlplus,xxx 可以为变量,即
VARIABLE var_name varchar2(10)
UPDATE table_name SET expr1
RETURNING column_name INTO :var_name;这里的 :var_name 使用的是绑定变量
另外,RETURNING 貌似可以与 RETURN通用
INSERT INTO VALUES 支持 RETURNING
INSERT INTO SELECT、 和MERGE 语句 不支持 RETURNING
例子1:
建表语句:
CREATE TABLE TEST111(
A1 VARCHAR(10),
A2 VARCHAR(20)
);
CREATE SEQUENCE TEST111_S1
START WITH 1
INCREMENT BY 1
CACHE 20
MAXVALUE 999999999999999999999999999
CYCLE;
DECLARE
SEQ NUMBER;
BEGIN
INSERT INTO TEST111 VALUES(TEST111_S1.NEXTVAL,'AAA2')
RETURNING A1 INTO SEQ;
DBMS_OUTPUT.PUT_LINE(SEQ);
END;
DECLARE
SEQ NUMBER;
BEGIN
INSERT INTO TEST111 VALUES(TEST111_S1.NEXTVAL,'AAA3');
SELECT TEST111_S1.CURRVAL INTO SEQ FROM DUAL;
COMMIT;
DBMS_OUTPUT.PUT_LINE(SEQ);
END; 例子2:
再另外,RETURNING 可以与BULK COLLECT 结合(批量绑定, 另外一个是 FORALL)
DECLARE
TYPE table_type IS TABLE OF column_name%TYPE;
v_tab table_type;
BEGIN
UPDATE table_name
SET expr1
RETURNING column_name BULK COLLECT INTO v_tab;
FOR i IN v_tab.first .. v_tab.last LOOP
DBMS_OUTPUT.put_line( l_tab(i));
END LOOP;
COMMIT;
END;ORA-06547:INSERT,UPDATE或DELETE语句必须使用RETURNING子句
产生这个错误的原因:
returning into子句作用于insert,update,delete,上而select则不行,应该用into。
报错的存储如下:
create or replace procedure p_stu_info(s_id number, s_name varchar2) is
v_namevarchar2(10);
v_agenumber;
v_ErrMsg varchar2(200);
begin
execute immediate 'select name,age from student_test where id=:1 and name=:2'
using s_id, s_name
returning into v_name, v_age;
dbms_output.put_line(v_name || '的年龄为:' || to_char(v_age));
exception
when others then
v_ErrMsg := SUBSTRB(SQLERRM, 1, 200);
dbms_output.put_line('找不到相应学生');
end p_stu_info;改成下面这样就ok了:
create or replace procedure p_stu_info(s_id number, s_name varchar2) is
v_namevarchar2(10);
v_agenumber;
v_ErrMsg varchar2(200);
begin
execute immediate 'select name,age from student_test where id=:1 and name=:2'
into v_name, v_age
using s_id, s_name;
dbms_output.put_line(v_name || '的年龄为:' || to_char(v_age));
exception
when others then
v_ErrMsg := SUBSTRB(SQLERRM, 1, 200);
dbms_output.put_line('找不到相应学生,错误原因:'||v_ErrMsg);
end p_stu_info;
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