[Java] Java正则表达式匹配不到结果的解决

String str = "\uFEFF<?xml version="1.0" encoding="utf-8"?><Response xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><Header ShouldRecordPerformanceTime="false" Timestamp="2018-6-25 21:24:03" RequestID="2c4d0b24-fd48-4a92-a2d8-c66793df2059" ResultCode="Success" AssemblyVersion="2.9.5.0" RequestBodySize="0" SerializeMode="Xml" RouteStep="1" Environment="pro" /><SSPATResponse><Result>0</Result><FareDetail /><Price>0</Price><ErrCode>102</ErrCode><DetailInfo>Send:APPLOCK\n" +
  "Rev:\n" +
  "可用资源锁定成功, 60 秒内没有输入指令资源将被Buk收回\n" +
  "Send:IG\n" +
  "Rev:\n" +
  "NO PNR\n" +
  "Send:\n" +
  "SS:AA186/N/27JUN18/PEKORD/NN1;\n" +
  "Rev:\n" +
  "AA 186 N 27JUN PEKORD NN1 WL OPEN \n" +
  "UNABLE TO SELL.PLEASE CHECK THE AVAILABILITY WITH "AV" AGAIN\n" +
  "Send:IG\n" +
  "Rev:</DetailInfo><PatOfficeno>SHA717</PatOfficeno></SSPATResponse><ResponseStatus><Timestamp xmlns="http://soa.ctrip.com/common/types/v1">2018-06-25T21:24:03.4535624+08:00</Timestamp><Ack xmlns="http://soa.ctrip.com/common/types/v1">Success</Ack></ResponseStatus></Response>";
 
String regex = "<DetailInfo>((.|\\n")*?)</DetailInfo>";

<DetailInfo>((.|\\n|\\r\\n")*?)</DetailInfo>

String.matches(regex);

Pattern.compile(regex).matcher(str).find()

public boolean matches(String regex) {
  return Pattern.matches(regex, this);
}
Pattern.matches(regex, this)

public static boolean matches(String regex, CharSequence input) {
  Pattern p = Pattern.compile(regex);
  Matcher m = p.matcher(input);
  return m.matches();
}

public static Pattern compile(String regex) {
  return new Pattern(regex, 0);
}
Pattern.matcher

public Matcher matcher(CharSequence input) {
  if (!compiled) {
    synchronized(this) {
    if (!compiled)
      compile();
    }
  }
  Matcher m = new Matcher(this, input);
  return m;
}

public boolean find() {
  int nextSearchIndex = last;
  if (nextSearchIndex == first)
    nextSearchIndex++;
  // If next search starts before region, start it at region
  if (nextSearchIndex < from)
    nextSearchIndex = from;
  // If next search starts beyond region then it fails
  if (nextSearchIndex > to) {
    for (int i = 0; i < groups.length; i++)
    groups[i] = -1;
    return false;
  }
  return search(nextSearchIndex);
}