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[Java] Java8 实现stream将对象集合list中抽取属性集合转化为map或list

编程语言 编程语言 发布于:2021-08-17 11:09 | 阅读数:411 | 评论:0

首先新建一个实体类Person
@Data
public class Person {
 /** 编码 */
 private String code;
 /** 名字 */
 private String name;
 public Person(String code, String name) {
  this.code = code;
  this.name = name;
 }
}
实例化三个对象放入list集合中
public static void main(String[] args) {
 Person person1 = new Person("001", "张三");
 Person person2 = new Person("002", "李四");
 Person person3 = new Person("002", "王五");
 List<Person> personList = new ArrayList<>();
 personList.add(person1);
 personList.add(person2);
 personList.add(person3);
 personList.forEach(t -> System.out.println(t.toString()));
}
输出结果为:
Person(code=001, name=张三)
Person(code=002, name=李四)
Person(code=002, name=王五)
1.抽取对象的code作为key,name作为value转化为map集合
方法为
private static HashMap<String, String> listToMap(List<Person> personList) {
 return (HashMap<String, String>)personList.stream()
   .filter(t -> t.getName()!=null)
   .collect(Collectors.toMap(Person::getCode,Person::getName,(k1,k2)->k2));
}
filter() 方法作用是过滤掉名字为空的对象,当对象的名字为null时,会出现NPE空指针异常
(k1,k2)->k2 意思是遇到相同的key时取第二个值
(k1,k2)->k1 意思是遇到相同的key时取第一个值
调用这个方法
HashMap<String,String> personMap = listToMap(personList);
personMap.forEach((k,v)-> System.out.println(k.toString() + " - " + v.toString()));
输出结果为:
001 - 张三
002 - 王五
2.抽取对象的name得到name的list集合
方法为
private static List<String> getNameList(List<Person> personList) {
 return personList.stream().map(Person::getName).collect(Collectors.toList());
}
调用这个方法
List<String> nameList = getNameList(personList);
nameList.forEach(t -> System.out.println(t.toString()));
输出结果为:
张三
李四
王五
补充:java8 使用stream将List转成Map,或者从List对象中获取单个属性List,List中根据某个字段排序
1.学生类
import lombok.Data; 
@Data
public class Student{ 
 private String stuId; 
 private String name; 
 private String age; 
 private String sex; 
}
2.测试类
public class Test {
 public static void main(String[] args) {
 
  // 创建学生List
  List<Student> list = createStudentList();
 
  // 1.获取value为Student对象,key为学生ID的Map
  getStudentObjectMap(list);
 
  // 2.获取value为学生姓名,key为学生ID的Map
  getStudentNameMap(list);
 
  // 3.获取学生姓名List
  getStudentNameList(list);
 
  //4.List中删除学生id = 1的对象
 
  list.removeIf(student -> student.getStuId().equals(1));
 
  //5.如果StudentId为Long类型如何转?
 
  Map<String, String> mapStr = list.stream().collect(Collectors.toMap(student -> student.getStuId().toString(), student -> JSON.toJSONString(student)));
 
  //6.根据List中Student的学生姓名排序
  Collections.sort(list, (o1, o2) -> {
   if (o1.getName().compareTo(o2.getName()) > 0) {
  return 1;
   } else if (o1.getName().compareTo(o2.getName()) < 0) {
  return -1;
   } else {
  return 0;
   }
  });
  //7.List遍历
  List<String> listStr = new ArrayList<>(); 
  List<Student> listStu = new ArrayList<>(); 
  listStr.forEach(studentStr -> { 
   listStu.add(JSON.parseObject(studentStr, Student.class));
 
  });
 
  //List根据某个字段过滤、排序
  listStu.stream()
  .filter(student -> student.getSex().equals("女"))
  .sorted(Comparator.comparing(Student::getName))
  .collect(Collectors.toList());
 
  //List根据某个字段分组
  Map<String,List<Student>> sexGroupMap = listStu.stream()
        .collect(Collectors.groupingBy(Student::getSex));
  //如果Map中多个名称相同,则studentId用逗号间隔
  Map<String,String> studentNameIdMap = listStu.stream()
        .collect(toMap(Student::getName,Student::getStuId,(s,a)->s+","+a));
 }
 
 public static List<Student> createStudentList() {
  List<Student> list = new ArrayList<Student>();
  Student lily = new Student();
  lily.setStuId("1");
  lily.setName("lily");
  lily.setAge("14");
  lily.setSex("女");
  Student xiaoming = new Student();
  xiaoming.setStuId("2");
  xiaoming.setName("xiaoming");
  xiaoming.setAge("15");
  xiaoming.setSex("男");
  list.add(lily);
  list.add(xiaoming);
  return list;
 }
 
 public static Map<Object, Object> getStudentObjectMap(List<Student> list) {
  Map<Object, Object> map = list.stream().collect(Collectors.toMap(Student::getStuId, student -> student));
  map.forEach((key, value) -> {
   System.out.println("key:" + key + ",value:" + value);
  });
  return map;
 }
 
 public static Map<String, String> getStudentNameMap(List<Student> list) {
  Map<String, String> map = list.stream().collect(Collectors.toMap(Student::getStuId, Student::getName));
  map.forEach((key, value) -> {
   System.out.println("key:" + key + ",value:" + value);
  });
  return map;
 }
 
 public static List<String> getStudentNameList(List<Student> list) {
  List<String> result = list.stream().map(student -> student.getName()).collect(Collectors.toList());
  for (String name : result) {
   System.out.println("name:" + name);
  }
  return result;
 }
}
以上为个人经验,希望能给大家一个参考,也希望大家多多支持CodeAE代码之家。如有错误或未考虑完全的地方,望不吝赐教。
原文链接:https://blog.csdn.net/weixin_44905182/article/details/105079266

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