[PHP] TP5框架简单登录功能实现方法示例

public function login()
{
  if(request()->isGet()){
    return view('login');
  }elseif(request()->isPost()){
    $model = new InfoModel(); 
    $name = input('name'); //获取表单提交的姓名
    $pwd = input('password');//获取表单提交的密码
    if($model->LoginVerify($name,$pwd)){
    $verify = input('code'); //获取验证码的值
    $cap = new Captcha(); //实例化验证码类
    if($cap->check($verify)){
      $this->success('登录成功','admin/ShowIndex');//登录成功跳转首页
      /*echo '登录成功';*/
    }else{
      $this->error('验证码错误','admin/admin/login');
    }
    }
  }
}

<div class="form-group">
  <div class="field field-icon-right">
    <input type="password" class="input input-big" name="password" placeholder="登录密码" data-validate="required:请填写密码" />
    <span class="icon icon-key margin-small"></span>
  </div>
  </div>
  <div class="form-group">
  <div class="field">
    <input type="text" class="input input-big" name="code" placeholder="填写右侧的验证码" data-validate="required:请填写右侧的验证码" />
    <img src="{:captcha_src()}" alt="" width="150" height="32" class="passcode" &omicron;nclick="this.src=this.src+'?'"> 
  </div>
</div>

<?php
namespace app\admin\model;
use think\Model;
class Info extends Model
{
#登录验证
  public function LoginVerify($name,$pwd)
  {
  //$re = $this->where(["username =>'$name',pwd=>'$pwd'"])->find();
  $re = $this->where("username='$name' and pwd='$pwd'")->find();
  if($re){
    return $re;
  }else{
    return null;
  }
  }
}