[Java] java实现可逆加密算法

package cn.exam.signup.service.pay.util;
 
import java.math.biginteger;
import java.util.arrays;
 
public class encrutil {
 private static final int radix = 16;
 private static final string seed = "0933910847463829232312312";
 
 public static final string encrypt(string password) {
 if (password == null)
  return "";
 if (password.length() == 0)
  return "";
 
 biginteger bi_passwd = new biginteger(password.getbytes());
 
 biginteger bi_r0 = new biginteger(seed);
 biginteger bi_r1 = bi_r0.xor(bi_passwd);
 
 return bi_r1.tostring(radix);
 }
 
 public static final string decrypt(string encrypted) {
 if (encrypted == null)
  return "";
 if (encrypted.length() == 0)
  return "";
 
 biginteger bi_confuse = new biginteger(seed);
 
 try {
  biginteger bi_r1 = new biginteger(encrypted, radix);
  biginteger bi_r0 = bi_r1.xor(bi_confuse);
 
  return new string(bi_r0.tobytearray());
 } catch (exception e) {
  return "";
 }
 }
 
 public static void main(string args[]){
 system.out.println(arrays.tostring(args));
 if(args==null || args.length!=2) return;
 if("-e".equals(args[0])){
  system.out.println(args[1]+" encrypt password is "+encrypt(args[1]));
 }else if("-d".equals(args[0])){
  system.out.println(args[1]+" decrypt password is "+decrypt(args[1]));
 }else{
  system.out.println("args -e:encrypt");
  system.out.println("args -d:decrypt");
 }
 }
 
}

[-e, 1234567890]
1234567890 encrypt password is 313233376455276898a5
[-d, 313233376455276898a5]
313233376455276898a5 decrypt password is 1234567890