[C++] [C语言] 链表的实现

#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>

//静态链表
struct LinkNode
{
  int num; //数据域
  struct LinkNode* next;  //指针域
};

int main()
{
  //创建节点
  struct LinkNode node1 = { 10,NULL };
  struct LinkNode node2 = { 20,NULL };
  struct LinkNode node3 = { 30,NULL };
  struct LinkNode node4 = { 40,NULL };
  struct LinkNode node5 = { 50,NULL };

  //建立关系
  node1.next = &node2;
  node2.next = &node3;
  node3.next = &node4;
  node4.next = &node5;

  //遍历链表
  struct LinkNode* pCurrent = &node1;
  while (pCurrent != NULL)
  {
  printf("%d\n",pCurrent->num);
  pCurrent = pCurrent->next;
  }
  return 0;
}

#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
#include <stdlib.h>
//动态链表
struct LinkNode
{
  int num; //数据域
  struct LinkNode* next;  //指针域
};

int main()
{
  //创建节点 开辟空间
  struct LinkNode *node1 = malloc(sizeof(struct LinkNode));
  struct LinkNode *node2 = malloc(sizeof(struct LinkNode));
  struct LinkNode *node3 = malloc(sizeof(struct LinkNode));
  struct LinkNode *node4 = malloc(sizeof(struct LinkNode));
  struct LinkNode *node5 = malloc(sizeof(struct LinkNode));

  //给数据域赋值
  node1->num = 10;
  node2->num = 20;
  node3->num = 30;
  node4->num = 40;
  node5->num = 50;

  //建立关系
  node1->next = node2;
  node2->next = node3;
  node3->next = node4;
  node4->next = node5;
  node5->next = NULL;

  //遍历链表
  struct LinkNode * pCurrent = node1;
  while (pCurrent != NULL)
  {
  printf("%d\n", pCurrent->num);
  pCurrent = pCurrent->next;
  }

  //释放
  free(node1);
  free(node2);
  free(node3);
  free(node4);
  free(node5);

  node1 = NULL;
  node2 = NULL;
  node3 = NULL;
  node4 = NULL;
  node5 = NULL;
  return 0;
}

• node.num        node->num     两者的区别是node类型不同
• 动态链表最后一个节点的指针域要置空 防止野指针