[C++] 【C语言】习题---递归函数

• //打印123 4
  
• //打印12 3 4
  
• //打印1 2 3 4
  

void print(int n){  if(n>9)  //n>9，则至少是两位数  {  print(n/10);  }   printf("%d  ",n%10);}int main(){  unsigned int num=0;  scanf("%d",&num);//1234  //递归  print(num);  return 0;}

int length(char* str){  int count=0;  while(*str!='\0')  {  count++;  *str++;//地址+1  }   return count;}int main(){  char arr[]="abc";  int len = length(arr);  printf("len=%d",len);  return 0;}

int function(int n){  int i=0;  int ret=1;  for(i=1;i<=n;i++)  {  ret=ret*i;  }  return ret;}int main(){  int ret=0 ;  int n=0;  scanf("%d",&n);  ret=function(n);  printf("%d",ret);}

int Fib(int n){  if(n<=2)  return 1;  else  return Fib(n-1)+Fib(n-2);}int main(){  int n=0;  int ret=0;  scanf("%d",&n);  ret=Fib(n);  printf("%d\n",ret);}

VS /test15