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[PHP] Laravel 框架返回状态拦截代码

开发技术 开发技术 发布于:2021-11-08 14:03 | 阅读数:376 | 评论:0

今天小编就为大家分享一篇Laravel 框架返回状态拦截代码,具有很好的参考价值,希望对大家有所帮助。一起跟随小编过来看看吧
可拦截系统的返回的状态自己在单独处理。
使用查询
composer require betterde/response
// 安装后直接调用以下
# stored
return stored($data, $message = '创建成功');
 
#updated
return updated($data, $message = '更新成功');
 
#deleted
return deleted($message = '删除成功');
 
#accepted
return accepted($message = '请求已接受,等待处理');
 
#notFound
return notFound($message = '您访问的资源不存在');
 
#internalError
return internalError($message = '未知错误导致请求失败');
 
#failed
return failed($message, $code = Response::HTTP_BAD_REQUEST);
 
#success
return success($data);
 
#message
return message($message, $code = Response::HTTP_OK);
 
#respond
return respond($data = [], $message = '请求成功', array $header = []);
拦截代码
App\Exceptions\Handler
<?php
 
namespace App\Exceptions;
 
use Exception;
use Illuminate\Support\Facades\Log;
use Illuminate\Database\QueryException;
use App\Traits\Response\InterfaceResponse;
use Illuminate\Auth\AuthenticationException;
use Illuminate\Validation\ValidationException;
use Illuminate\Auth\Access\AuthorizationException;
use Illuminate\Database\Eloquent\ModelNotFoundException;
use Symfony\Component\HttpKernel\Exception\HttpException;
use Illuminate\Foundation\Exceptions\Handler as ExceptionHandler;
use Symfony\Component\HttpKernel\Exception\NotFoundHttpException;
use Symfony\Component\HttpKernel\Exception\UnauthorizedHttpException;
 
/**
 * 异常处理
 *
 * Date: 21/03/2018
 * @author George
 * @package App\Exceptions
 */
class Handler extends ExceptionHandler
{
  use InterfaceResponse;
 
 /**
  * 定义不需要记录的异常类
  *
  * @var array
  */
 protected $dontReport = [
    HttpException::class,
    ValidationException::class,
    ModelNotFoundException::class,
    AuthorizationException::class,
    AuthenticationException::class,
  ];
 
 /**
  * A list of the inputs that are never flashed for validation exceptions.
  *
  * @var array
  */
 protected $dontFlash = [
  'password',
  'password_confirmation',
 ];
 
  /**
   * 定义需要记录的异常
   *
   * Date: 21/03/2018
   * @author George
   * @param Exception $exception
   * @return mixed|void
   * @throws Exception
   */
 public function report(Exception $exception)
 {
  parent::report($exception);
 }
 
  /**
   * 拦截异常并生成对应的响应内容
   *
   * Date: 21/03/2018
   * @author George
   * @param \Illuminate\Http\Request $request
   * @param Exception $exception
   * @return \Illuminate\Contracts\Routing\ResponseFactory|\Symfony\Component\HttpFoundation\Response
   */
 public function render($request, Exception $exception)
 {
  // 拦截数据库操作异常
//  if ($exception instanceof QueryException) {
//    Log::error($exception);
//    return $this->internalError();
//    }
 
    // 拦截一般异常并生成响应
    if ($exception instanceof GeneralException) {
      return failed($exception->getMessage(), $exception->getCode() ?: 500);
    }
 
    // 拦截404异常
    if ($exception instanceof ModelNotFoundException) {
      return $this->notFound();
    }
 
    // 拦截授权异常
    if ($exception instanceof AuthorizationException) {
      return failed('您无权访问', 403);
    }
 
    // 参数验证错误的异常,我们需要返回 400 的 http code 和一句错误信息
    if ($exception instanceof ValidationException) {
      return failed(array_first(array_collapse($exception->errors())), 422);
    }
 
    // 用户认证的异常,我们需要返回 401 的 http code 和错误信息
    if ($exception instanceof UnauthorizedHttpException) {
      return failed('未提供Token', 401);
    }
 
    // 捕获404异常
    if ($exception instanceof NotFoundHttpException) {
    return $this->notFound();
    }
 
  return parent::render($request, $exception);
 }
 
  /**
   * 认证失败后抛出异常
   *
   * Date: 2018/5/27
   * @author George
   * @param \Illuminate\Http\Request $request
   * @param AuthenticationException $exception
   * @return \Illuminate\Http\JsonResponse|\Illuminate\Http\Response
   */
  public function unauthenticated($request, AuthenticationException $exception)
  {
    return failed('身份认证失败', 401);
 }
}
以上这篇Laravel 框架返回状态拦截代码就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持CodeAE代码之家
原文链接:https://blog.csdn.net/qq_29755359/article/details/82107389

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